Two metallic wires made from copper have same length but the radius of wire 1 is half of that of wire 2. The resistance of wire 1 is R. If both the wires are joined together in series, the total resistance becomes

2R
R/2
5R/4
3R/4
5R/4  So, resistance of Wire 2 is R/4 as radius is half of wire 1, so area would be 4 times of wire 1._x000D_ Now for resistance in series. R= R1 + R2._x000D_ Therefore, Final R= R + R/4 = 5R/4

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