Physics
A ball is thrown vertically upward from the ground. It crosses a point at the height of 25 m twice at an interval of 4 seconds. The ball was thrown with the velocity of
18 m/s
25 m/s
30 m/s
36 m/s
30 m/s
The interval between object pass the same point is 4 sec._x000D_
That means in 2 sec, object reaches the top and in next 2 sec, it again reaches the same point._x000D_
By the info given, we can find the velocity of that point by using : v=u+(-gt)_x000D_
0= u – 10ร2_x000D_
u = 20_x000D_
Then the velocity at 25m is 20m/sec._x000D_
so the initial velocity is_x000D_
โv = u + (โ2gh)_x000D_
400 = u โ 2x 10 x 25_x000D_
u = 900_x000D_
=> u = 30 m/s
30 m/s The interval between object pass the same point is 4 sec._x000D_
That means in 2 sec, object reaches the top and in next 2 sec, it again reaches the same point._x000D_
By the info given, we can find the velocity of that point by using : v=u+(-gt)_x000D_
0= u – 10ร2_x000D_
u = 20_x000D_
Then the velocity at 25m is 20m/sec._x000D_
so the initial velocity is_x000D_
โv = u + (โ2gh)_x000D_
400 = u โ 2x 10 x 25_x000D_
u = 900_x000D_
=> u = 30 m/s
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