Measures of Dispersion
If the maximum value in a series is 25 and its range is 15, the minimum value of the series is:
10
15
25
35
15
Given; maximum value is 25, range is 15. find the minimum value.
Solution:
step 1of 2
Define range
For a given set of observations range is define as the difference between maximum value and minimum value.
Step 2of 2
Find minimum value
Maximum value=25
Range=15
Maximum value-minimum value=15
25-minimum value=15
Minimum value=25-15
MINIMUM VALUE=10
15 Given; maximum value is 25, range is 15. find the minimum value.
Solution:
step 1of 2
Define range
For a given set of observations range is define as the difference between maximum value and minimum value.
Step 2of 2
Find minimum value
Maximum value=25
Range=15
Maximum value-minimum value=15
25-minimum value=15
Minimum value=25-15
MINIMUM VALUE=10
Related posts
Which measure of dispersion can be computed in case of openend classes?A. Standard deviation
B. Range
C. Quartile deviation
D. Coefficient of variation
The scatter in a series of values about the average is called:
A. Central tendency
B. Dispersion
C. Skewness
D. Symmetry
The sum of absolute deviations is minimum if these deviations are taken from the:
A. Mean
B. Mode
C. Median
D. Upper quartile
Study of scatteredness of observations is known as :
A. Measure of dispersion
B. Standard deviation
C. Measure of central tendency
D. None of the above
If there are many extreme scores on all examination, the dispersion is:
A. Large
B. Small
C. Normal
D. Symmetric
The measure of dispersion which is expressed in terms of the nits of observations:
A. Absolute measure
B. Variance
C. Relative measure
D. None of the above
The standard deviation is independent of:
A. Change of origin
B. Change of scale of measurement
C. Change of origin and scale of measurement
D. Difficult to tell
2 responses to “If the maximum value in a series is 25 and its range is 15, the minimum value of the series is:”
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the minimum value is 10. Given; maximum value is 25, range is 15. find the minimum value.
solution.
step 1of 2
Define range
For a given set of observations range is define as the difference between maximum value and minimum value.
Step 2of 2
Find minimum value
Maximum value=25
Range=15
Maximum value-minimum value=15
25-minimum value=15
Minimum value=25-15
MINIMUM VALUE=10-
thank you for providing solution
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