Physics
A person lifts luggage of 20 kg from the ground and puts it on his head 2m above the ground. Calculate the work done by him. (g = 10 )
20 J
400J
200J
40J
400J
Total work done in lifting and moving the luggage is 588 Joules._x000D_
Explanation :_x000D_
1. work done in lifting the luggage_x000D_
= potential energy of the luggage_x000D_
= mgh_x000D_
where,_x000D_
m = mass = 20 kg_x000D_
g = acceleration due to gravity = 9.8 m/sยฒ_x000D_
h = height = 3 m_x000D_
Hence,_x000D_
P = mgh = 20 x 9.8 x 3_x000D_
= 588 J_x000D_
2. work done in moving the object,_x000D_
Since now weight of the luggage is acting in downward direction and the movement is in horizontal direction, hence work done in moving the luggage is zero because component of force along horizontal direction is zero._x000D_
Total work done = 588 + 0 = 588 J._x000D_
Hence total work done in lifting and moving the luggage 588 J.
400J Total work done in lifting and moving the luggage is 588 Joules._x000D_
Explanation :_x000D_
1. work done in lifting the luggage_x000D_
= potential energy of the luggage_x000D_
= mgh_x000D_
where,_x000D_
m = mass = 20 kg_x000D_
g = acceleration due to gravity = 9.8 m/sยฒ_x000D_
h = height = 3 m_x000D_
Hence,_x000D_
P = mgh = 20 x 9.8 x 3_x000D_
= 588 J_x000D_
2. work done in moving the object,_x000D_
Since now weight of the luggage is acting in downward direction and the movement is in horizontal direction, hence work done in moving the luggage is zero because component of force along horizontal direction is zero._x000D_
Total work done = 588 + 0 = 588 J._x000D_
Hence total work done in lifting and moving the luggage 588 J.
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