Skip to content
MCQtimes.com
GK
Pakistan Studies
Current Affairs
Islamic Studies
English
MCQtimes.com
Toggle Menu
Electrostatics
Home
/
Physics
/
Electrostatics
Show/Hide Answers
Electrostatics
According to Coulomb’s law, how does the repulsion between two positively charged objects change as the distance between them increases?
increases
decreases
remains unchanged
can not be determined
As per coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects _____ As per Coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects decreases. Coulomb’s law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as: F = k * q1 * q2 / r^2 Where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant. As we can see from the formula, the force of attraction between two positively charged objects decreases as the distance of separation between them increases. This is because the force of attraction between the charges is inversely proportional to the square of the distance between them. Therefore, as the distance between them increases, the force of attraction decreases, and the charges are less likely to be drawn towards each other.
Author:
rikazzz
Comment
Electrostatics
By using electroscope, if the body is negatively charged then due to electrostatic induction, then on the disk there will be appear
both positive and negative charges
negative charge
positive charge
no charge
Author:
rikazzz
Comment
Electrostatics
To store a large amount of charge at relatively low voltage, we use
ceramic capacitors
fixed capacitors
parallel plate capacitors
electrolytic capacitors
Author:
rikazzz
Comment
Electrostatics
The electric field 30cm away from a light bulb is roughly
15 NC
-1
12 NC
-1
10 NC
-1
5 NC
-1
Author:
rikazzz
Comment
Electrostatics
As per Coulomb’s law, the force of attraction or repulsion between two point charges is inversely proportional to the
sum of the magnitude of charges
square of the distance between them
product of the magnitude of charges
cube of the distance
Author:
rikazzz
Comment
Electrostatics
If we bring charged plastic rod near-neutral aluminum rod, then rods will
repel each other
attract each other
remain their position
exchange charges
Author:
rikazzz
Comment
Electrostatics
The superior type of capacitor and used in vast ranges of application is
ceramic capacitors
fixed capacitors
parallel plate capacitors
electrolytic capacitors
Author:
rikazzz
Comment
Electrostatics
If 5 J of work is required to shift 10 C charge from one place to another then the potential difference is
0.5 V
2 V
5 V
10 V
Author:
rikazzz
Comment
Electrostatics
If F is the force acting on the test charge q
o
, the electric field intensity E would be given by
E = F – q
o
E = F/q
o
E = F + q
o
E = q
o
/F
Author:
rikazzz
Comment
Electrostatics
If 2 bodies are oppositely charged with 400µC and 200µC, the distance between them in the air is 0.5 m. The force between the bodies should be
2880 N
3000 N
1850 N
3250 N
Author:
rikazzz
Comment
Page navigation
1
2
3
…
13
Next Page
Next
Go to Page
Light
Dark
GK
Pakistan Studies
Current Affairs
Islamic Studies
English