Physics
If a person moves a trolley for a distance of 10 m with a force of 50 N, then the work done is
0.2 J
5 J
20 J
500 J
500 J
distance of trolley S = 10m_x000D_
force F =50N_x000D_
work done = F. S_x000D_
=50ร10_x000D_
=500J
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