Electrostatics
According to Coulomb’s law, how does the repulsion between two positively charged objects change as the distance between them increases?
increases
decreases
remains unchanged
can not be determined
decreases
As per coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects _____
As per Coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects decreases.
Coulomb’s law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as:
F = k * q1 * q2 / r^2
Where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.
As we can see from the formula, the force of attraction between two positively charged objects decreases as the distance of separation between them increases. This is because the force of attraction between the charges is inversely proportional to the square of the distance between them. Therefore, as the distance between them increases, the force of attraction decreases, and the charges are less likely to be drawn towards each other.
decreases As per coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects _____
As per Coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects decreases.
Coulomb’s law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as:
F = k * q1 * q2 / r^2
Where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.
As we can see from the formula, the force of attraction between two positively charged objects decreases as the distance of separation between them increases. This is because the force of attraction between the charges is inversely proportional to the square of the distance between them. Therefore, as the distance between them increases, the force of attraction decreases, and the charges are less likely to be drawn towards each other.
Related posts
Due to electrostatic induction in aluminum rod due to charged plastic rod, the total charge on the aluminum rod isA. zero
B. positive
C. negative
D. dual
In the combination of parallel capacitors, the right plate of each capacitor is connected to the battery’s
A. no terminal
B. both negative and positive terminals
C. negative terminal
D. positive terminal
The electrostatic force acting on two charges of 1C separated by 1m is about
A. 4ร109
B. 6ร109
C. 8ร109
D. 9ร109
The amount of work done in bringing unit positive charge from infinity to a point in electric field is called
A. coulomb’s force
B. electrostatic force
C. electric potential
D. resistance
The spacing between field lines shows their
A. direction
B. position
C. strength
D. none of above
One micro coulomb is equal to
A. 10-6
B. 10-8
C. 10-4
D. 10-9
The property of attraction or repulsion between substances is due to the
A. electric charges
B. neutrons
C. atoms
D. capacitors
3 responses to “According to Coulomb’s law, how does the repulsion between two positively charged objects change as the distance between them increases?”
-
why it is??
-
Question updated
-
-
There is no any attraction between two positively charged electrons but repulsion between two positively charged electrons occur so as the distance increase it remains unchanged
Leave a Reply to Heer Cancel reply