Electrostatics
According to Coulomb’s law, how does the repulsion between two positively charged objects change as the distance between them increases?
increases
decreases
remains unchanged
can not be determined
decreases
As per coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects _____
As per Coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects decreases.
Coulomb’s law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as:
F = k * q1 * q2 / r^2
Where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.
As we can see from the formula, the force of attraction between two positively charged objects decreases as the distance of separation between them increases. This is because the force of attraction between the charges is inversely proportional to the square of the distance between them. Therefore, as the distance between them increases, the force of attraction decreases, and the charges are less likely to be drawn towards each other.
decreases As per coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects _____
As per Coulomb’s law, when the distance of separation increases, the attraction of 2 positively charged objects decreases.
Coulomb’s law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as:
F = k * q1 * q2 / r^2
Where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.
As we can see from the formula, the force of attraction between two positively charged objects decreases as the distance of separation between them increases. This is because the force of attraction between the charges is inversely proportional to the square of the distance between them. Therefore, as the distance between them increases, the force of attraction decreases, and the charges are less likely to be drawn towards each other.
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3 responses to “According to Coulomb’s law, how does the repulsion between two positively charged objects change as the distance between them increases?”
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why it is??
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Question updated
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There is no any attraction between two positively charged electrons but repulsion between two positively charged electrons occur so as the distance increase it remains unchanged
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